An element X (At. wt. = 80 g / mol ) having fcc structure, calculate no. of unit cells in 8 gm of X:

0.4 \times N_{A}

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0.1 \times N_{A}

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4 \times N_{A}

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None of these

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Solution

The correct option is D None of these
Effective no. of atoms in a unit cell $= 4$ N
No. of atoms $= \frac{8}{80} \times N_{A}$
$∴$ No. of unit cell $= \frac{N_{A}}{10} \times \frac{1}{4}$

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X

8 g m

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m o l^{- 1}

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4

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