Question

An elevator descends into a mine shaft at the of 6 Min/m . If the descent starts from 10m above the ground level, how long will it take to reach- 350m

Answer 1

Distance descended is denoted by a negative integer.

Initial height = +10 m

Final depth = −350 m

Total distance to be descended by the elevator = (−350) − (+10) = −360 m

Time taken by the elevator to descend −6 m = 1 min

Thus, time taken by the elevator to descend −360 m = (−360) ÷ (−6)

= 60 minutes = 1 hour