Question

An elevator descends into a mine shaft at the rate of 6m per minute . If it begins to its descend from 15 m above the ground level and what will be it's position after 45 m

Answer 1

An elevator descends into mine shaft at the rate of 6 meter per minute.
So for 1 min elevator descends 6 metres.
The position of the elevator after one hour = we know 1 hour =60 min, so 60min x 6metres = 360 meters..
But the elevator began to descend from 15 meters above, so 360-15 = 345metres.

And its position after 45 mins is 45metres x 6 mins = 270 meters.
And the elevator has descended from 15 meters above so 270 - 15 meters="255metres."

Hope it helps!