An equilateral triangle ABC is inscribed in a circle with centre O. Then, ∠BOC is equal to ___.
Given that ΔABC is equilateral.
⟹∠BAC=60∘
Since the angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle, we have
∠BOC=2 ∠BAC=2×60∘=120∘.