An ice-berg floating partly immersed in sea water of density $1.03 g / c m^{3}$ . The density of ice is $0.92 g / c m^{3}$ . The fraction of the total volume of the iceberg above the level of sea water is

8.1 %

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11 %

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34 %

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0.8 %

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Solution

The correct option is A $11 %$
Let $v$ be the volume of the ice-berg outside the sea water and $V$ be the total volume of ice-berg. Then as per question
$0.92 V = 1.03 (V - v)$
or, $\frac{v}{V} = 1 - \frac{0.92}{1.03} = \frac{11}{103}$
$∴ \frac{v}{V} \times 100 = 11 \times \frac{100}{103} ≅ 11 %$

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An ice-berg floating partly immersed in sea water of density 1.03g/cm3. The density of ice is 0.92g/cm3. The fraction of the total volume of the iceberg above the level of sea water is

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