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Question

An ideal transformer has 500 primary turns and 10 secondary turns. The primary coil carries current 2 A and its voltage is 11,000 V. Current and voltage in the secondary coil will be

A
100 A,220 V
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B
0.04 A,220 V
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C
100 A,550000 V
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D
0.04 A,550000 V
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Solution

The correct option is C 100 A,550000 V

From the above circuit of a transformer, applying KVL

E1+N1(dϕdt)=0 (primary coil)
E2=N2(dϕdt)=i2R (secondary coil)

E1E2=N1N2

where N1 and N2 are no of turns in primary and secondary coil.

i.e 11,000E2=50010
E2=11,00050=220 V

For calculating currents, I2I1=N1N2
I22=50010
I2=100 A

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