Question

An inclined plane rises 1 in 10. If length of the inclined plane is 5 $m$, find the height of the raised end above the horizontal.

• A. $\frac{5}{\sqrt{101}}m$
• B. $\frac{5}{\sqrt{100}}m$
• C. $5\sqrt{100}m$
• D. $\frac{5}{\sqrt{102}}m$

Answer 1

The correct option is A $\frac{5}{\sqrt{101}}m$

Let $h$ be the horizontal raise $tan\theta =\frac{1}{10}$
$sin\theta =\frac{1}{\sqrt{({10}^2+1^2)}}=\frac{1}{\sqrt{101}}=\frac{h}{5}$Therefore,$h=\frac{5}{\sqrt{101}}m$