An object at rest starts moving. It covers a distance of 2 m in one second. It covers a further distance of 5 m in two seconds in the same direction. What is its average velocity and acceleration?

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Solution

$u = 0, s = 2 m, t = 1 s$
$s = u t + \frac{1}{2} a t^{2}$
$2 = 0 + \frac{1}{2} a \times 1$
$a = 4 m / s^{2}$
Average velocity $= \frac{t o t a l d i s p l a c e m e n t}{t o t a l t i m e}$
$= \frac{2 + 5}{1 + 2} = \frac{7}{3}$
average velocity= $\frac{7}{3}$
acceleration= $4 m / s^{2}$

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An object at rest starts moving. It covers a distance of 2 m in one second. It covers a further distance of 5 m in two seconds in the same direction. What is its average velocity and acceleration?

u=0,s=2m,t=1ss=ut+12at22=0+12a×1a=4m/s2Average velocity=totaldisplacementtotaltime=2+51+2=73average velocity=73acceleration=4m/s2

$u = 0, s = 2 m, t = 1 s$
$s = u t + \frac{1}{2} a t^{2}$
$2 = 0 + \frac{1}{2} a \times 1$
$a = 4 m / s^{2}$
Average velocity $= \frac{t o t a l d i s p l a c e m e n t}{t o t a l t i m e}$
$= \frac{2 + 5}{1 + 2} = \frac{7}{3}$
average velocity= $\frac{7}{3}$
acceleration= $4 m / s^{2}$