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Standard XII

Physics

Distance

An object of ...

Question

An object of mass 10 kg. moves at a constant speed of $10 m s^{- 1}$ . A constant force acts for 4 s on the object and gives it a speed of $2 m s^{- 1}$ in opposite direction. The force acting on the object is.

-3N

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-30 N

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30 N

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Solution

The correct option is B -30 N
Mass of object, m = 10 kg
Initial speed, u = 10 m/s
Time, dt = 4s
Final speed, v = -2 m/s
Force, F = $\frac{d p}{d t} = \frac{m v - m u}{d t} = \frac{- 10 \times 2 x - 10 \times 10}{4}$
$= - 30$

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An object of mass 10 kg. moves at a constant speed of 10ms−1. A constant force acts for 4 s on the object and gives it a speed of 2ms−1 in opposite direction. The force acting on the object is.

The correct option is B -30 NMass of object, m = 10 kg Initial speed, u = 10 m/sTime, dt = 4s Final speed, v = -2 m/sForce, F = dpdt=mv−mudt=−10×2x−10×104=−30

An object of mass 10 kg. moves at a constant speed of $10 m s^{- 1}$ . A constant force acts for 4 s on the object and gives it a speed of $2 m s^{- 1}$ in opposite direction. The force acting on the object is.

The correct option is B -30 N
Mass of object, m = 10 kg
Initial speed, u = 10 m/s
Time, dt = 4s
Final speed, v = -2 m/s
Force, F = $\frac{d p}{d t} = \frac{m v - m u}{d t} = \frac{- 10 \times 2 x - 10 \times 10}{4}$
$= - 30$