Question

An object undergoes an acceleration of 8 ms^-2 starting from rest. Find the distance traveled in 4 seconds.

Answer 1

Step (1) :Given:

The acceleration produced in the object, $a=8m{s}^{-2}$

The object is initially at rest. Hence, the initial velocity, $u=0m/s$

Time taken by the object $t=4sec$

Step (2) :Finding the distance traveled by the object by using the 2nd equation of motion:

We know that $\begin{array}{l}Dis\tan ce,s=ut+\frac{1}{2}a{t}^2\end{array}$

By substituting the given values, we get

$$\begin{gathered} s=0\times 4+\frac{1}{2}\left(8\right){\left(4\right)}^2 \\ =0+\left(4\right){\left(4\right)}^2 \\ =64m \end{gathered}$$

Hence, the given object travels 64 m in 4 sec.