Question

An open vessel at 27°C is heated until two fifth of the air (assumed as an ideal gas) in it has escaped from the vessel. Assuming that the volume of the vessel remains constant, the temperature at which the vessel has been heated is:

• A. 750°C
• B. 500°C
• C. 750 K
• D. 500 K

Answer 1

The correct option is D 500 K

$\frac{2}{5}$ air escaped from vessel,
$\therefore \frac{3}{5}$ air remain in vessel.
P and V are constant
So, $n_1{T}_1=n_2{T}_2$
$n_1\left(300\right)=\left(\frac{3}{5}{n}_1\right)T_2\Rightarrow T_2=500K$