Question

An $X$-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45\times {10}^{-2}\mathring{A}$. The maximum energy of a photon in the radiation in $eV$ is $(h=6.62\times {10}^{-34}J-s,c=3\times {10}^{8}m/s)$

• A. $27,500$
• B. $22,500$
• C. $17,500$
• D. $12,500$

Answer 1

The correct option is A $27,500$

$E=\frac{hc}{\lambda }$
$=\frac{6.62\times {10}^{-34}\times 3\times {10}^8}{45\times {10}^{-12}}$
$=\frac{0.44\times {10}^{-14}}{1.6\times {10}^{-19}}$
$=0.275\times {10}^{5}eV$