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Question

Anne, Benne and Cenne are three friends. Benne takes 2 days more than Cenne to complete the work. If Anne started a work and 3 days later Benne joins him, then the work gets completed in 3 more days. Working together Anne, Benne and Cenne can complete thrice the original work in 6 days. In how many days Benne can complete twice the original work with double the efficiency working alone?


A

2

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B

3

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C

4

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D

6

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Solution

The correct option is D

6


From the last statement: Efficiency of Anne (A), Benne (B) and Cenne (C) = 50% From the first statement: Number of days taken by B is 2 more than C. From the second statement. Anne worked for 6 days and Benne had worked for 3 days only. Now, consider option (d). Number of days taken by B = 6, Efficiency = 16.66% It means Benne had completed 16.66×3=50% work in 3 days. Therefore Anne had completed 50% work in 6 days. Thus, the efficiency of Anne =8.33%(506) Hence, the efficiency of Cenne = 50 - (16.66 + 8.33) = 25% Thus B takes 6 days (efficiency=16.66%) and C takes 4 days (efficiency=25%) which is true according to the first statement, hence option (d) is correct. From the last statement: Efficiency of Anne (A), Benne (B) and Cenne (C) = 50% From the first statement: Number of days taken by B is 2 more than C. From the second statement. Anne worked for 6 days and Benne had worked for 3 days only. Now, consider option (d). Number of days taken by B = 6, Efficiency = 16.66% It means Benne had completed 16.66×3=50% work in 3 days. Therefore Anne had completed 50% work in 6 days. Thus, the efficiency of Anne =8.33%(506) Hence, the efficiency of Cenne = 50 - (16.66 + 8.33) = 25% Thus B takes 6 days (efficiency=16.66%) and C takes 4 days (efficiency=25%) which is true according to the first statement, hence option (d) is correct.


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