Aqueous solution of light greenish crystalline compound reacts with potassium ferricyanide to give a deep blue coloured solution or precipitate. Its chemical formula is:

F e F e [F e (C N)_{6}]_{2}

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F e_{4} [F e (C N)_{6}]_{2}

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F e_{3} [F e (C N)_{6}]_{2}

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Solution

The correct option is C $F e_{3} [F e (C N)_{6}]_{2}$
Iron exists in two forms: ferrous and ferric.
Ferrous is light greenish crystalline compound which when reacts with potassium ferricyanide, gives a deep blue coloured solution or precipitate.
$F e^{2 +} + K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} + 3 K^{+}$
On the other hand, ferric reacts with potassium ferrocyanide, to give a reddish brown precipitate.

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Similar questions

Q. A light bluish green crystalline compound responds to the following tests:
(i) Its aqueous solution gives a brown precipitate or colouration with alkaline

K_{2} [{H g I}_{4}]

solution.
(ii) Its aqueous solution gives a blue colour with

K_{3} [{F e (C N)}_{6}]

solution.
(iii) Its solution in hydrochloric acid gives a white precipitate with

{B a C l}_{2}

solution. The molecular formula of the compound is

F e S O_{4} . (N H_{4})_{2} S O_{4} . 6 H_{2} O

(Mohr's salt)

If the given statement is true enter 1 else enter 0.

Q. (A) (yellow coloured solution) changes to light green coloured solution (B) on passing

H_{2} S

gas. (A) and (B) both give white precipitate with

B a {C l}_{2}

solution, insoluble in conc.

H C l

. A gives blue coloured ppt (C) with

K_{4} [{F e (C N)}_{6}]

, (B) does not. Here,
(A) :

{F e C l}_{3}

(B) :

{F e C l}_{2}

F e_{4} [F e (C N_{6})]_{3}

If true enter 1, else enter 0.

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:
(a) $N a_{4} [F e (C N)_{6}]$ (b) $F e_{4} [F e (C N)_{6}]^{3}$ (c) $F e_{2} [F e (C N)_{6}]$ (d) $F e_{3} [F e (C N)_{6}]_{4}$