1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Introduction to Oxidation and Reduction
Arrange order...
Question
Arrange order with respect to oxidation no :
S
O
2
−
4
,
S
2
O
2
−
4
A
S
O
2
−
4
<
S
2
O
2
−
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
S
2
O
2
−
4
=
S
O
2
−
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
S
O
2
−
4
>
S
2
O
2
−
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none o these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
S
O
2
−
4
>
S
2
O
2
−
4
Oxidation number os
S
in
S
O
2
−
4
is
=
6
S
2
O
2
−
4
is
+
3
S
O
2
−
4
>
S
2
O
2
−
4
increasing order
Suggest Corrections
0
Similar questions
Q.
The oxidation state of sulphur in the anions
S
O
2
−
3
,
S
O
2
−
4
,
S
2
O
2
−
4
,
S
2
O
2
−
6
is in the order :
Q.
The oxidation states of sulphur in the anions
S
O
2
−
3
,
S
2
O
2
−
4
a
n
d
S
2
O
2
−
6
and follows the order:
Q.
Arrange the following in correct order with respect to oxidation state of S.
S
O
2
−
3
,
S
2
O
2
−
4
and
S
2
O
2
−
6
Q.
The oxidation states of sulphur in the anions
S
O
2
−
3
,
S
2
O
2
−
4
and
S
2
O
2
−
6
follow the order
Q.
The oxidation states of sulphur in
S
2
O
2
−
4
is :
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Introduction
CHEMISTRY
Watch in App
Explore more
Introduction to Oxidation and Reduction
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app