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Valency and Oxidation State

Arrange the f...

Question

Arrange the following in correct order with respect to oxidation state of S.
$S O_{3}^{2 -}, S_{2} O_{4}^{2 -}$ and $S_{2} O_{6}^{2 -}$

A

S_{2} O_{4}^{2 -} < S O_{3}^{2 -} < S_{2} O_{6}^{2 -}

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B

S O_{3}^{2 -} < S_{2} O_{4}^{2 -} < S_{2} O_{6}^{2 -}

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C

S_{2} O_{4}^{2 -} < S_{2} O_{6}^{2 -} < S O_{3}^{2 -}

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D

S_{2} O_{6}^{2 -} < S_{2} O_{4}^{2 -} < S O_{3}^{2 -}

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Solution

The correct option is A $S_{2} O_{4}^{2 -} < S O_{3}^{2 -} < S_{2} O_{6}^{2 -}$
Oxidation state of S in
$S_{2} O_{4}^{2 -} = + 3$
$S O_{3}^{2 -} = + 4$
$S_{2} O_{6}^{2 -} = + 5$
Hence, the correct order is $S_{2} O_{4}^{2 -} < S O_{3}^{2 -} < S_{2} O_{6}^{2 -}$ .

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