Arrange the following haloalkanesin the increasing order of density.Justify your answer.
CCl4 ,CH2Cl3, CHCl3

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Solution

The density order is
CCl₄ > CHCl₃> CH₂Cl₂

The reason is CCl₄ has zero dipole moment and it shows it has symmetrical arrangement. Lesser the dipole, more compact arrangement will be there resulting in more density.

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Similar questions

C H_{3} C l

C H_{2} C l_{2}

C H C l_{3}

C C l_{4}

{C H}_{3} C l, {C H}_{2} {C l}_{2}, C H {C l}_{3}, C {C l}_{4}

{C H}_{3} C l > {C H}_{2} {C l}_{2} > C H {C l}_{3} > C {C l}_{4}

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}, C C l_{4}

C C l_{4}

C H_{3} C l

C H_{4} = C C l_{4} < C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l

C C l_{4}, C H C l_{3}

C H_{4}

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