As one considers orbits with higher values of n in a hydrogen atom, the electric potential energy of the atom

decreases

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increases

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remains the same

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does not increase.

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Solution

The correct option is B increases
Total energy of the electron in nth orbit $E_{n} = \frac{- 13.6}{n^{2}} e V$
Potential energy $P . E = 2 E_{n} = \frac{- 27.2}{n^{2}} e V$
Thus potential energy of the atom increases with increase in $n$ .

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As one considers orbits with higher values of n in a hydrogen atom, the electric potential energy of the atom

The correct option is B increasesTotal energy of the electron in nth orbit En=−13.6n2 eVPotential energy P.E=2En=−27.2n2 eV Thus potential energy of the atom increases with increase in n.

The correct option is B increases
Total energy of the electron in nth orbit $E_{n} = \frac{- 13.6}{n^{2}} e V$
Potential energy $P . E = 2 E_{n} = \frac{- 27.2}{n^{2}} e V$
Thus potential energy of the atom increases with increase in $n$ .