Question

As shown above, a magnetic force of ${10}^{-14}$ N is experienced by a charge particle moving with speed of ${10}^6$ m/s in a uniform magnetic field B of magnitude ${10}^{-2}$ T. Calculate the magnitude of the charge.

• A. ${10}^{-22}$ C
• B. ${10}^{-18}$ C
• C. ${10}^{-10}$ C
• D. ${10}^{-6}$ C
• E. ${10}^{-2}$ C

Answer 1

The correct option is B ${10}^{-18}$ C

Given : $F_m={10}^{-14}$ N ;$B={10}^{-2}$ T ;$v={10}^6$ m/s

Using $F_m=|q|vB$

$\therefore$ ${10}^{-14}=|q|\times {10}^6\times {10}^{-2}$

$⟹$ $|q|={10}^{-18}$ C