Assign oxidation number to the underlined element in $H_{4} {P - -}_{2} O_{7}$

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Solution

Let X be the oxidation state of P in $H_{4} P_{2} O_{7}$ .
$4 (+ 1) + 2 X + 7 (- 2) = 0$
$X = + 5$
Hence, the oxidation state of P in $H_{4} P_{2} O_{7}$ is +5.

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