Assign oxidation number to the underlined element in $N a B - - H_{4}$

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Solution

Let $x$ be the oxidation number of B in $N a B H_{4}$ .
We know that oxidation no. of both H and Na is +1.
$+ 1 + x + 4 (- 1) = 0$
$x = + 3$
Hence, the oxidation no. of B is +3.

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