Assume that the total surface area of a human body is 1.6 $m^{2}$ and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37 $^{\circ}$ C.Stefan constant $σ$ is $6.0 \times 10^{- 8} W / m^{2} - K^{4}$ .

608 J

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887 J

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1026 J

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902 J

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Solution

The correct option is B
887 J

Stefan's law: $\frac{Δ Q}{Δ t} = e σ A T^{4}$

For an ideal radiator e = 1 $\Rightarrow \frac{Δ Q}{Δ t} = 6 \times 10^{- 8} \times 1.6 \times (273 + 37)^{4}$

= $6 \times 10^{- 8} \times 1.6 \times 314 \times 104$

= 887 J per second.

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Assume that the total surface area of a human body is 1.6 $m^{2}$ and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37 $^{\circ}$ C.Stefan constant $σ$ is $6.0 \times 10^{- 8} W / m^{2} - K^{4}$ .

Q. Assume that the total surface area of a human body is 1.6 m² and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37°C. Stefan constant σ is 6.0 × 10⁻⁸ W m⁻² K⁻⁴.

Assume that the total surface area of a human body is 1.6 $m^{2}$ and that it radiates like an ideal radiator. Calculate the amount of enrgy radiated per second by the body if the body temperature is $37^{0}$ C. Stefan constant $σ$ is $6.0 \times 10^{- 8} W m^{- 2} K^{- 4}$ .

Q. Calculate the amount of heat radiated per second by a body of surface area

12 {c m}^{2}

kept in thermal equilibrium in a room temperature

20^{o} C

. The emissivity of the surface

= 0.80

and

σ = 6.0 \times 10^{- 8} W / m^{2} - K^{4}

An electric heater emits 1000 W of thermal radiation. The coil has a surface area of 0.020 $m^{2}$ . Assuming that the coil radiates like a blackbody, find its temperature. $σ = 6.00 \times 10^{- 8} W / m^{2} - K^{4}$ .

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Assume that the total surface area of a human body is 1.6 m2 and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37∘ C.Stefan constant σ is 6.0×10−8W/m2−K4.

The correct option is B 887 J Stefan's law: ΔQΔt=eσAT4 For an ideal radiator e = 1 ⇒ΔQΔt=6×10−8×1.6×(273+37)4 =6×10−8×1.6×314×104 = 887 J per second.

Assume that the total surface area of a human body is 1.6 $m^{2}$ and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37 $^{\circ}$ C.Stefan constant $σ$ is $6.0 \times 10^{- 8} W / m^{2} - K^{4}$ .

The correct option is B
887 J

Stefan's law: $\frac{Δ Q}{Δ t} = e σ A T^{4}$

For an ideal radiator e = 1 $\Rightarrow \frac{Δ Q}{Δ t} = 6 \times 10^{- 8} \times 1.6 \times (273 + 37)^{4}$

= $6 \times 10^{- 8} \times 1.6 \times 314 \times 104$

= 887 J per second.