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Ion Electron Method

Assume the fo...

Question

Assume the following reaction is carried out in acidic medium.
$6 e^{-} + C r_{2} {O_{7}}^{2 -} ⟶ 2 {C r}^{3 +} + 7 H_{2} O$

How many $H^{+}$ do we need to add to the LHS to balance the H atoms?

A

10

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B

6

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C

7

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D

14

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Solution

The correct option is D
14

Count number of Hydrogen on right hand side 7 $\times$ 2 = 14
Hence, add 14 $H^{+}$ ions to the side which is deficient.
$C r_{2} {O_{7}}^{2 -} + 6 e^{-} + 14 H^{+} ⟶ 2 {C r}^{3 +} + 7 H_{2} O$

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Assume the following reaction is carried out in acidic medium.
$6 e^{-} + C r_{2} {O_{7}}^{2 -} ⟶ 2 {C r}^{3 +} + 7 H_{2} O$

How many $H^{+}$ do we need to add to the LHS to balance the H atoms?

Assume the following reaction is carried out in acidic medium.
$6 e^{-}$ + $C r_{2} {O_{7}}^{2 -}$ $⟶$ 2 ${C r}^{3 +}$ + $7 H_{2} O$

How many $H^{+}$ do we need to add to the LHS to balance the H atoms?

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