You visited us 1 times! Enjoying our articles? Unlock Full Access!

Molecular Mass

Assuming full...

Question

Assuming fully decomposed, the volume of $C O_{2}$ released at STP on heating 9.85 g of $B a C O_{3}$ will be: (Atomic mass of Ba=137)

0.84 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.24 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.06 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.12 L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 1.12 L
$B a C O_{3} \to B a O + C O_{2}$
When 197 grams of $B a C O_{3}$ is decomposed it forms 22.4 liters of $C O_{2}$
If 9.85 grams of $B a C O_{3}$ is decomposed it forms X liters of $C O_{2}$ .
$X = \frac{9.85 \times 22.4}{197} = 1.12$ .
Hence volume is 1.12 liters

Suggest Corrections

Similar questions

C O_{2}

9.85 g

B a C O_{3}

B a = 137

C O_{2}

B a C O_{3}

C O_{2}

B a C O_{3}

C O_{2}

9.85

B a C O_{3}

B a

137

C O_{2}

B a C O_{3}

B a C O_{3} = 197

Join BYJU'S Learning Program