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Standard XII

Physics

Moment of Inertia of a Disc

At 11 atm and...

Question

At 11 atm and $27^{o} C$ volume of a balloon filled with a gas is 500 ml. The stretching capacity of the balloon is 33 times the volume of the gas at $1$ atm.The temperature above which the balloon bursts is:

900^{o} C

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300^{o} C

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627^{o} C

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627 K

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Solution

The correct option is B $627^{o} C$
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

$\frac{500}{300} = \frac{1500}{T_{2}}$

Thus, $T_{2} = 900 K = 627^{0} C$

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At 11 atm and 27oC volume of a balloon filled with a gas is 500 ml. The stretching capacity of the balloon is 33 times the volume of the gas at 1atm.The temperature above which the balloon bursts is:

The correct option is B 627oCV1T1=V2T2500300=1500T2Thus, T2=900K=6270C

At 11 atm and $27^{o} C$ volume of a balloon filled with a gas is 500 ml. The stretching capacity of the balloon is 33 times the volume of the gas at $1$ atm.The temperature above which the balloon bursts is:

The correct option is B $627^{o} C$
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

$\frac{500}{300} = \frac{1500}{T_{2}}$

Thus, $T_{2} = 900 K = 627^{0} C$