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Question

At 87oC, the following equilibrium is established:
H2(g)+S(s)H2S(g),Kc=8×102
If 0.3 mole of hydrogen and 2 mole of sulphur are heated to 87oC in a 2 L vessel, what will be the partial pressure of H2S at equilibrium.

A
0.32 atm
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B
1.43 atm
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C
0.62 atm
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D
4.0 atm
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Solution

The correct option is A 0.32 atm
For reaction,
H2(g)+S(s)H2S(g)
0.3x x
KC=[H2S(g)][H2(g)]8×102=x0.3x
0.0240.08x=x
0.024=1.08 x
x=0.022
P=nRTV
PH2S=0.022×0.08×36020.32 atm

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