AT CONSTANT TEMPERATURE, THE GAS IS AT A PRESSURE OF 940mm OF Hg. AT WHAT PRESSURE, IT'S VOLUME DECREASES BY 40%?

Open in App

Solution

p1 = 940 mm,
v1 = x,
p2 = y,
v2 = x - (40% of v1).

v2 = x - (40 * x) / 100

p1v1 = k = p2v2

940x = k = y * (x - 40x / 100)

940x = y * (60x / 100)

940x = (3x / 5) * y

y = (940x * 5) / 3x

y = 4700/3 = 1566.67 mmHg

So the new pressure of the gas is 1566.67 mm Hg.

Suggest Corrections

Similar questions

Q. The volume of a certain gas at constant temperature was found to be

1200 c m^{3}

when pressure is

1000 m m

H g

. If the pressure is decreased by

30 %

, find the new volume.

Q. Assertion :Volume : temperature ratio is constant for a fixed amount of gas at constant pressure. Reason: At constant pressure the volume of a given mass of a gas increases or decreases by

1 / 273

of its volume at

0^{o} C

$800 c m^{3}$ of gas is collected at 650 mm pressure. At what pressure would the volume of the gas reduce by 40% of its original volume, temperature remaining constant?

Q. A certain mass of a gas occupies a volume of 600

m l

at a certain temperature and pressure. If pressure is decreased by 40% what will be the volume occupied by the same mass of the gas at the same temperature?

The volume of a gas at constant pressure increases by 2% when the temperature is increased by 5 $^{0}$ K, It's initial temperature is

Join BYJU'S Learning Program

AT CONSTANT TEMPERATURE, THE GAS IS AT A PRESSURE OF 940mm OF Hg. AT WHAT PRESSURE, IT'S VOLUME DECREASES BY 40%?

p1 = 940 mm, v1 = x, p2 = y, v2 = x - (40% of v1). v2 = x - (40 * x) / 100 p1v1 = k = p2v2 940x = k = y * (x - 40x / 100) 940x = y * (60x / 100) 940x = (3x / 5) * y y = (940x * 5) / 3x y = 4700/3 = 1566.67 mmHg So the new pressure of the gas is 1566.67 mm Hg.

p1 = 940 mm,
v1 = x,
p2 = y,
v2 = x - (40% of v1).

v2 = x - (40 * x) / 100

p1v1 = k = p2v2

940x = k = y * (x - 40x / 100)

940x = y * (60x / 100)

940x = (3x / 5) * y

y = (940x * 5) / 3x

y = 4700/3 = 1566.67 mmHg

So the new pressure of the gas is 1566.67 mm Hg.