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Reactivity with Halogens and Hydrogen (Group 2)

Be Cl 2 +LiAl...

Question

$B e {C l}_{2} + L i A l H_{4} ⟶ X + L i C l + A l {C l}_{3}$ :

X

is lithium hydride

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X

B e H_{2}

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X

B e {C l}_{2} \cdot 2 H_{2} O

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X

L i H

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Solution

The correct option is A $X$ is $B e H_{2}$
$2 B e {C l}_{2} + L i A l H_{4} ⟶ 2 B e H_{2} + L i C l + A l {C l}_{3}$
$(X)$
So $X$ would be $B e H_{2}$
Hence option B is correct.

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