Boyle's law gives the expression :

{(d P / d V)}_{T} = K / V

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{(d P / d V)}_{T} = - K / V^{6}

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{(d P / d V)}_{T} = - K / V^{4}

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V \propto 1 / P

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Solution

The correct option is D $V \propto 1 / P$

Boyle's law states that at constant temperature the volume of a given mass of a dry gas is inversely proportional to its pressure.
Which is expressed as, $V \propto 1 / P$

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Similar questions

(d P / d V)_{T} = K / V

(d P / d V)_{T} = - K / V^{2}

Boyle's law may be represented as

1.[dp/dv]T=K/V

2.[dp/dv]T=-K/V

3.[dp/dv]T=-K/V

4.[dp/dv]T=K/V^2

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In the adjoining figure, ABCD and PQRC are rectangles, where Q is the midpoint of AC. Then DP is equal to

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