Boyle's law may be represented as:
where, $K = c o n s t a n t$ .

{(\frac{d P}{d V})}_{T} = K / V

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{(\frac{d P}{d V})}_{T} = - \frac{K}{V}

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(\frac{d P}{d V}) = - \frac{K}{V^{2}}

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{(\frac{d P}{d V})}_{T} = \frac{K}{V^{2}}

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Solution

The correct option is C $(\frac{d P}{d V}) = - \frac{K}{V^{2}}$
According to Boyle's law,
$P V = K$
$P = \frac{K}{V}$
$\frac{d P}{d V} = - \frac{K}{V^{2}}$

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Similar questions

Boyle's law may be represented as

1.[dp/dv]T=K/V

2.[dp/dv]T=-K/V

3.[dp/dv]T=-K/V

4.[dp/dv]T=K/V^2

(d P / d V)_{T} = - K / V^{2}

(d P / d V)_{T} = K / V

\frac{d P}{d V} = 0

Boyle's law is represented by the equation PV=K (K is not constant), K depends on

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