$B r - C H = C H - C H_{2} - C H = C H - C H_{2} - C H = C = C = C H - C H = C (C H_{3})_{2}$
Total number of geometrical isomers for the given compound is:

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Solution

There are 3 stereochemical centre which can show geometrical isomerisms.
$∴ 2^{3} = 8$ geometricl isomers are possible.

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