By how much is $a^{4} + 4 a^{2} b^{2} + b^{4}$ more than $a^{4} - 8 a^{2} b^{2} + b^{4}$ ?

12 a^{2} b^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 12 a^{2} b^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 a^{4} + 2 b^{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $12 a^{2} b^{2}$
$a^{4} + 4 a^{2} b^{2} + b^{4}$
$a^{4} - 8 a^{2} b^{2} + b^{4}$
$-$ $+$ $-$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 12 a^{2} b^{2} - ----- -$

Suggest Corrections

Similar questions

a^{4} + 4 a^{2} b^{2} + b^{4}

a^{4} - 8 a^{2} b^{2} + b^{4}

x^{3} - 2 x^{2} y + 3 x y^{2} - y^{3}, 2 x^{3} - 5 x y^{2} + 3 x^{2} y - 4 y^{3}

a^{4} - 2 a^{3} b + 3 a b^{3} + 4 a^{2} b^{2} + 3 b^{4}, - 2 a^{4} - 5 a b^{3} + 7 a^{3} b - 6 a^{2} b^{2} + b^{4}

a^{4} - 3 a^{2} b^{2} + b^{4}

3 a^{4} - 2 a^{2} b^{2} + b^{4} + 3 a^{2} b + 2 a b^{2} .

If X = 1 - a^{2} and Y = 1 - b^{2}, then what is X^{2} + Y^{2} ?

(a + b + c)^{4} - (b + c)^{4} - (c - a)^{4} - (a + b)^{4} + a^{4} + b^{4} + c^{4}

Join BYJU'S Learning Program