Question

By what number should $\frac{-33}{16}$ be divided to get $\frac{-11}{4}?$

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{number}be\mathrm{x}. \\ \therefore \frac{-33}{16}÷\mathrm{x}=\frac{-11}{4} \\ \mathrm{or}\frac{-33}{16}\times \frac{1}{\mathrm{x}}=\frac{-11}{4} \\ \mathrm{or}\frac{1}{\mathrm{x}}=\frac{-11}{4}\times \frac{16}{-33} \\ \mathrm{or}\frac{1}{\mathrm{x}}=\frac{4}{3} \\ \mathrm{or}\mathrm{x}=\frac{3}{4} \\ Thus,\mathrm{the}\mathrm{number}\mathrm{is}\frac{3}{4}. \end{gathered}$$