Question

By what number should $\frac{-33}{8}$ be divided to get $\frac{-11}{2}$?

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{number}\mathrm{be}\mathrm{x}. \\ \mathrm{Now}, \\ \frac{-33}{8}÷\mathrm{x}=\frac{-11}{2} \\ \Rightarrow \frac{-33}{8}\times \frac{1}{\mathrm{x}}=\frac{-11}{2} \\ \Rightarrow \frac{1}{\mathrm{x}}=\frac{-11}{2}÷\frac{-33}{8} \\ \Rightarrow \frac{1}{\mathrm{x}}=\frac{-11}{2}\times \frac{8}{-33} \\ \Rightarrow \frac{1}{\mathrm{x}}=\frac{88}{66} \\ \Rightarrow \frac{1}{\mathrm{x}}=\frac{4}{3} \\ \Rightarrow \mathrm{x}=\frac{3}{4}(\mathrm{Reciprocal}\mathrm{of}\frac{4}{3}) \end{gathered}$$