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Enthalpy of Combustion

C3H2g + H2g →...

Question

$C_{3} H_{2} (g) + H_{2} (g) \to C_{2} H_{6} (g) + C H_{4} (g) △ H^{0} = ?$
$C_{2} H_{6}$ (g) $H_{2} (g)$ $C H_{4} (g)$ C graphite $C_{3} H_{2}$ (g)
-1560.1 -225.0 -090.0 -393.5 -2220
$△ H^{0} c o m b u s t i o n (K J m o l^{- 1}$

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Solution

$C_{3} H_{2} + 4 H_{2} ⟶ C_{2} H_{6} + C H_{4}$
$△ H^{\circ} = (△ H)_{p r o d u c t} - (△ H)_{r e a c t a n t s} = (- 1560 - 90) - [- 222 + 4 (- 225)] = - 528 K J m o l^{- 1}$

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C_{3} H_{8} (g) + H_{2} (g) ⟶ C_{2} H_{6} (g) + C H_{4} (g)

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Compound:	$H_{2} (g)$	$C H_{4} (g)$	$C_{2} H_{6} (g)$	$C (g r a p h i t e)$
$Δ H^{⊖} (k J m o l^{- 1}) :$	$- 285.8$	$- 890.0$	$- 1560.0$	$- 393.5$

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$C_{2} H_{6}$ (g)	$H_{2} (g)$	$C H_{4} (g)$	C graphite	$C_{3} H_{2}$ (g)
-1560.1	-225.0	-090.0	-393.5	-2220