(c) Mass of all the wagons except wagon 1 is 4×2000 = 8000 kg
Acceleration of the wagons = 3.5 ms−2
Thus, force exerted on all the wagons except wagon 1 = 8000×3.5 = 28000 N
Therefore, the force exerted by wagon 1 on the remaining four wagons is 28000 N.
Hence, the force exerted by wagon 1 on wagon 2 is 28000 N.