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Percentage Composition

CaC2+H2O→C2H2...

Question

$C a C_{2} + H_{2} O \to C_{2} H_{2} + C a {(O H)}_{2}$
The reaction of calcium carbide and water produces acetylene gas ( $C_{2} H_{2}$ ) and calcium hydroxide.
What volume of $C_{2} H_{2}$ will form from $0.200 m o l$ $C a C_{2}$ which reacts with an excess of water? Assume the gas will be at STP conditions.

0.200 L

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4.5 L

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2.25 L

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2.4 L

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Solution

The correct option is D $4.5 L$
$C a C_{2} + H_{2} O \to C_{2} H_{2} + C a (O H)_{2}$
$1 m o l e$ of $C a C_{2}$ produce $22.4 L i t r e s$ of acetylene at STP.
$1 m o l e$ $C a C_{2} \to$ $22.4 L i t r e s$ Acetylene
$0.2 m o l e$ $C a C_{2} \to$ $0.2 \times 22.4 = 4.48 L i t r e s$ Acetylene $\approx 4.5 L i t r e s$
So, $4.5 L i t r e s$ of acetylene is produced.

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