Question

${CaCO}_3\underrightarrow{Heat}CaO+CO\uparrow$
From the above equation calculate the amount of carbon dioxide in grams librated by heating $25g$ of calcium carbonate.

Answer 1

The equation is given as,

${CaCO}_3⟶CaO+CO\uparrow$

1mole of ${CaCO}_3$ reacts to make 1 mole of ${CO}_2$

Then by taking mole ratios

$=\frac{n_{{CaCO}_3}}{n_{C{O}_2}}$

$=\frac{1}{1}$

$\frac{givenweight}{molecularweight}=n$

$\frac{\frac{25}{100}}{\frac{X}{44}}=\frac{1}{1}$

$11=x$

Hence $11g$ of ${CO}_2$