Calculate -f Ho in kJ magnitude only for chloride ion in aq- from the following data- 12H2g - 12Cl2g - HClg- -f Ho-92-4 kJHClg- H2Ol - H3O- aq-Cl-aq- - Ho-74-8 kJ-fHo of H-aq-0-0 kJ

Given, 12H_2(g)+ (aq)→ H^+(aq); Δ H^o=0...(i) 12H_2(g) +12Cl_2(g) → HCl(g); Δ H^o= 92.4 kJ...(ii) HCl(g)+ H_2O(l) → H_3O^++ (aq)+Cl^ (aq); Δ H^o= 74. ...

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Byju's Answer

Standard XII

Chemistry

Scales of Electronegativity

Calculate Δf ...

Question

Calculate $Δ_{f} H^{o} in kJ$ (magnitude only) for chloride ion (in aq.) from the following data:
$\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); Δ_{f} H^{o} = - 92.4 kJ H C l (g) + H_{2} O (l) \to H_{3} O^{+} + (a q) + C l^{-} (a q); Δ H^{o} = - 74.8 kJ$
$Δ_{f} H^{o} of H^{+} (a q) = 0.0 kJ$

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Solution

Given,
$\frac{1}{2} H_{2} (g) + (a q) \to H^{+} (a q); Δ H^{o} = 0... (i)$
$\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); Δ H^{o} = - 92.4 kJ . . . (i i) H C l (g) + H_{2} O (l) \to H_{3} O^{+} + (a q) + C l^{-} (a q); Δ H^{o} = - 74.8 kJ (i i i)$
By inspection method,
$Equation (i i) + (i i i) - (i) reveals that$
$\frac{1}{2} C l_{2} (g) + (a q) \to C l^{-} (a q); Δ H = - 167.2 kJ$
$∴ Heat formation of C l^{-} (a q) = - 167.2 kJ$

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Similar questions

Q. Calculate

Δ H_{f}^{o}

for chloride ion from the following data:

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g)

Δ H = - 92.4

H C l (g) + N H_{2} O

(excess)

\to H^{+} (a q) + C l^{-} (a q)

Δ H = - 74.8

Δ H_{f}^{o} (H^{+} (a q)) = 0.0

KJ.

Q. Calculate

△ H_{f}^{\circ}

for chloride ion from the following data :

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); △ H_{f}^{\circ} = - 92.4 k J

H C l (g) + n H_{2} O \to H^{+} (a q) + C l^{-} (a q); △ H^{\circ} = - 74.8 k J

△ H_{f}^{\circ} H^{+} (a q) = 0.0 k J

Q. Calculate

{Δ H}_{f}^{o}

for chloride ion from the following data:

\frac{1}{2} H_{2} (g) + \frac{1}{2} {C l}_{2} (g ⟶ H C l (g); Δ H = - 92.4 k J {m o l}^{- 1}

H C l (g) + n H_{2} O ⟶ H^{+} (a q .) + {C l}^{-} (a q .); Δ H = - 74.8 k J {m o l}^{- 1}

Δ H_{f (H^{+} (a q .)}^{o} = 0.0 k J {m o l}^{- 1}

Q. All of the following statements are true for the reaction given below except which of the following statement?

H C l (g) + H_{2} O (l) \to H_{3} O^{+} (a q) + C l^{-} (a q)

Δ G^{o}

of the cell reaction

A g C l (s) + 1 / 2 H_{2} (g) \to A g (s) + H^{+} (a q .) + {C l}^{-} (a q)

- 21.52 k J

Calculate the EMF for the cell reaction:

2 A g C l (c) + H_{2} (g) \to A g (s) + 2 H^{+} (a q .) + 2 {C l}^{-} (a q .)

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Calculate ΔfHoin kJ (magnitude only) for chloride ion (in aq.) from the following data: 12H2(g)+12Cl2(g)→HCl(g); ΔfHo=−92.4 kJHCl(g)+H2O(l)→H3O++(aq)+Cl−(aq); ΔHo=−74.8 kJ ΔfHoof H+(aq)=0.0 kJ

Given, 12H2(g)+(aq)→H+(aq); ΔHo=0...(i) 12H2(g)+12Cl2(g)→HCl(g); ΔHo=−92.4 kJ...(ii)HCl(g)+H2O(l)→H3O++(aq)+Cl−(aq); ΔHo=−74.8 kJ (iii) By inspection method, Equation (ii)+(iii)−(i) reveals that 12Cl2(g)+(aq)→Cl−(aq); ΔH=−167.2 kJ ∴Heat formation of Cl−(aq)=−167.2 kJ