Calculate H-f for chloride ion from the following data - 12H2g - 12Cl2g - HClg- H-f - -92-4 kJ HClg - nH2O - H-aq - Cl-aq- H- - -74-8 kJ H- fH-aq - 0-0 kJ-

You visited us 65 times! Enjoying our articles? Unlock Full Access!

Heat of Formation

Calculate H...

Question

Calculate $△ H_{f}^{\circ}$ for chloride ion from the following data :
$\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); △ H_{f}^{\circ} = - 92.4 k J$
$H C l (g) + n H_{2} O \to H^{+} (a q) + C l^{-} (a q); △ H^{\circ} = - 74.8 k J$
$△ H_{f}^{\circ} H^{+} (a q) = 0.0 k J$ .

Open in App

Solution

Suggest Corrections

Similar questions

Δ H_{f}^{o}

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g)

Δ H = - 92.4

H C l (g) + N H_{2} O

\to H^{+} (a q) + C l^{-} (a q)

Δ H = - 74.8

Δ H_{f}^{o} (H^{+} (a q)) = 0.0

{Δ H}_{f}^{o}

\frac{1}{2} H_{2} (g) + \frac{1}{2} {C l}_{2} (g ⟶ H C l (g); Δ H = - 92.4 k J {m o l}^{- 1}

H C l (g) + n H_{2} O ⟶ H^{+} (a q .) + {C l}^{-} (a q .); Δ H = - 74.8 k J {m o l}^{- 1}

Δ H_{f (H^{+} (a q .)}^{o} = 0.0 k J {m o l}^{- 1}

Δ_{f} H^{o} in kJ

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); Δ_{f} H^{o} = - 92.4 kJ H C l (g) + H_{2} O (l) \to H_{3} O^{+} + (a q) + C l^{-} (a q); Δ H^{o} = - 74.8 kJ

Δ_{f} H^{o} of H^{+} (a q) = 0.0 kJ

A l_{2} C l_{2}

2 A l (s) + 6 H C l (a q) \to A l_{2} C l_{6} (a q) + 3 H_{2} (g), △ H = - 239.76 k c a l

H_{2} (g) + C l_{2} (g) \to 2 H C l (g), △ H = - 44.0 k c a l

H C l (g) + A q \to H C l (a q), △ H = - 17.32 k c a l

A l_{2} C l_{6} (s) + A q \to A l_{2} C l_{6} (a q), △ H = - 153.69 k c a l

K O H

K_{(s)} + H_{2} O + a q \to {K O H}_{(a q)} + \frac{1}{2} H_{2}; Δ H = - 48.4 K . C a l

H_{2 (g)} + \frac{1}{2} O_{2 (g)} \to H_{2} O_{(l)}; Δ H = - 68.44 K . C a l

{K O H}_{(s)} + a q \to {K O H}_{(a q)}; Δ H = - 14.0 K . C a l

Join BYJU'S Learning Program