Calculate - H f o for chloride ion from the following data- 1 2 H 2 g- 1 2 Cl 2 g- HClg- H-92-4kJ mol -1 HClg-n H 2 O- H - aq- Cl - aq- H-74-8kJ mol -1 - H f H - aq- o -0-0kJ mol -1

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Heat of Formation

Calculate Δ...

Question

Calculate ${Δ H}_{f}^{o}$ for chloride ion from the following data:
$\frac{1}{2} H_{2} (g) + \frac{1}{2} {C l}_{2} (g ⟶ H C l (g); Δ H = - 92.4 k J {m o l}^{- 1}$
$H C l (g) + n H_{2} O ⟶ H^{+} (a q .) + {C l}^{-} (a q .); Δ H = - 74.8 k J {m o l}^{- 1}$
$Δ H_{f (H^{+} (a q .)}^{o} = 0.0 k J {m o l}^{- 1}$

- 167 k J {m o l}^{- 1}

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267 k J {m o l}^{- 1}

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167 k J {m o l}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 267 k J {m o l}^{- 1}

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Δ H_{f}^{o}

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g)

Δ H = - 92.4

H C l (g) + N H_{2} O

\to H^{+} (a q) + C l^{-} (a q)

Δ H = - 74.8

Δ H_{f}^{o} (H^{+} (a q)) = 0.0

△ H_{f}^{\circ}

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); △ H_{f}^{\circ} = - 92.4 k J

H C l (g) + n H_{2} O \to H^{+} (a q) + C l^{-} (a q); △ H^{\circ} = - 74.8 k J

△ H_{f}^{\circ} H^{+} (a q) = 0.0 k J

Δ_{f} H^{o} in kJ

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); Δ_{f} H^{o} = - 92.4 kJ H C l (g) + H_{2} O (l) \to H_{3} O^{+} + (a q) + C l^{-} (a q); Δ H^{o} = - 74.8 kJ

Δ_{f} H^{o} of H^{+} (a q) = 0.0 kJ

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g)

N H_{3} (g) + H C l (g) \to N H_{4} C l (s)

N H_{3} (g) + a q \to N H_{3} (a q),

Δ H = - 8.4 K . C a l .

H C l (g) + a q \to H C l (a q),

Δ H = - 17.3 K . C a l .

N H_{3} (a q) + H C l (a q) \to N H_{4} C l (a q), Δ H = - 12.5 K . C a l s .

N H_{4} C l (s) + a q \to N H_{4} C l (a q), Δ H = + 3.9 K . C a l .

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