1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XIII
Chemistry
Concentration Terms
Calculate mol...
Question
Calculate molality of 2.5 g of ethanoic acid
[
C
H
3
C
O
O
H
]
in 75 g of benzene.
A
0.551
m
o
l
k
g
−
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.556
m
o
l
k
g
−
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.558
m
o
l
k
g
−
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.552
m
o
l
k
g
−
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
0.556
m
o
l
k
g
−
1
MW of
C
H
3
C
O
O
H
=
60
g
m
o
l
−
1
m
=
w
2
×
1000
M
w
2
×
w
1
=
2.5
g
×
1000
60
g
m
o
l
−
1
×
75
g
=
0.556
m
o
l
k
g
−
1
Suggest Corrections
0
Similar questions
Q.
Calculate molality of 2.5 g of ethanoic acid
[
C
H
3
C
O
O
H
]
in 75 g of benzene.
Q.
Calculate molality of 2.5 grams of Ethanoic Acid
(
C
H
3
C
O
O
H
)
in 75 grams of Benzene.
Q.
Calculate the molality if 2.5 g of glucose is dissolved in 75 g of benzene.
Q.
Calculate the molarity of 2.5gm of ethanoic acid CH3COOH in 73 gm of benzene
Q.
Calculate molality of 2.5 g of ethanoic acid
[
C
H
3
C
O
O
H
]
in 75 g of benzene.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Concentration Terms
CHEMISTRY
Watch in App
Explore more
Concentration Terms
Standard XIII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app