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Hydrogen Peroxide

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Question

Calculate number of moles of $N a_{2} S_{2} O_{3}$ that will react with $I_{2}$ obtained when $1 m o l e$ of $K_{2} C r_{2} O_{7}$ reacts with excess of $K I$ in acidic medium.

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Solution

$C r_{2} O_{7}^{2 -} + 14 H^{+} + 6 I^{-} ⟶ 2 C r^{3 +} + 7 H_{2} O + 3 I_{2}$
$3 I_{2} + 6 N a_{2} S_{2} O_{3} ⟶ 3 N a_{2} S_{4} O_{6} + 6 N a I$
$1 m o l K_{2} C r_{2} O_{7} K I - - \to 3 m o l I_{2} \equiv 6 m o l N a_{2} S_{2} O_{3}$

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