Calculate the area of a trapezium whose length of the parallel sides are $30 cm$ and $20 cm$ and distance between the parallel lines is $15 cm$ .

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Solution

Area of a trapezium $= \frac{1}{2} \times$ (distance between two parallel sides) $\times$ (sum of two parallel slides)

$= \frac{1}{2} \times 15 \times (30 + 20) {cm}^{2}$

$= \frac{1}{2} \times 15 \times 50$

$= \frac{750}{2} = 375 {cm}^{2}$

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Calculate the area of a trapezium whose length of the parallel sides are 30 cm and 20 cm and distance between the parallel lines is 15 cm.

Area of a trapezium =12× (distance between two parallel sides) × (sum of two parallel slides)=12×15×(30+20) cm2=12×15×50=7502=375 cm2

Calculate the area of a trapezium whose length of the parallel sides are $30 cm$ and $20 cm$ and distance between the parallel lines is $15 cm$ .

Area of a trapezium $= \frac{1}{2} \times$ (distance between two parallel sides) $\times$ (sum of two parallel slides)

$= \frac{1}{2} \times 15 \times (30 + 20) {cm}^{2}$

$= \frac{1}{2} \times 15 \times 50$

$= \frac{750}{2} = 375 {cm}^{2}$