Question

Calculate the average oxidation number of element $Mn$ in the compound $M{n}_3{O}_4$.
(Report your answer upto two decimal place)

Answer 1

Let oxidation state of Mn is $x$.
Charge of $O=-2$

$\therefore 3x-8=0$
$\Rightarrow 3x=8\Rightarrow x=+\frac{8}{3}$
$\therefore \text{average oxidation number of Mn is}+\frac{8}{3}=2.66$