Calculate the current flowing through a nichrome wire, immersed in 100 g of oil at $20^{o} C$ , such that final temperature of oil rises to $80^{o} C$ in five minutes, when the supply of E.M.F is 10V. [Specific heat capacity of oil is $0.85 J g^{- 1}^{o} C^{- 1}$ ]

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Solution

Heat generated $= m s Δ T = 100 \times 0.85 \times 60 ° C$
$\frac{V^{2}}{R} t = 5100 \frac{10^{2} \times 5 \times 60}{R} = 5100 R = \frac{300}{51} = 5.88 c u r r e n t i = \frac{V}{R} = \frac{10}{5.88} = 1.7 A$

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Calculate the current flowing through a nichrome wire, immersed in 100 g of oil at 20oC, such that final temperature of oil rises to 80oC in five minutes, when the supply of E.M.F is 10V. [Specific heat capacity of oil is 0.85Jg−1 oC−1]

Heat generated =msΔT=100×0.85×60°C V2Rt=5100102×5×60R=5100R=30051=5.88currenti=VR=105.88=1.7A

Calculate the current flowing through a nichrome wire, immersed in 100 g of oil at $20^{o} C$ , such that final temperature of oil rises to $80^{o} C$ in five minutes, when the supply of E.M.F is 10V. [Specific heat capacity of oil is $0.85 J g^{- 1}^{o} C^{- 1}$ ]

Heat generated $= m s Δ T = 100 \times 0.85 \times 60 ° C$
$\frac{V^{2}}{R} t = 5100 \frac{10^{2} \times 5 \times 60}{R} = 5100 R = \frac{300}{51} = 5.88 c u r r e n t i = \frac{V}{R} = \frac{10}{5.88} = 1.7 A$