Calculate the e.m.f of the following cell reaction at 298K: Mg(s)+Cu2+(0.0001M)→Mg2+(0.001M)+Cu(s) The standard potential (Eo) of teh cell is 2.71V.
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Solution
Mg(s)+Cu2+(0.0001M)→Mg2+(0.001M)+Cu By Nernst equation the EMF of the cell at 298K is: E=Eo−0.05912log[Mg2+][Cu2+] =2.71−0.05912log0.0010.0001 =2.71−0.02955 =2.68V Thus, the EMF of the cell is 2.68V.