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Question

Calculate the e.m.f of the following cell reaction at 298K:
Mg(s)+Cu2+(0.0001M)Mg2+(0.001M)+Cu(s)
The standard potential (Eo) of teh cell is 2.71V.

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Solution

Mg(s)+Cu2+(0.0001M)Mg2+(0.001M)+Cu
By Nernst equation the EMF of the cell at 298K is:
E=Eo0.05912log[Mg2+][Cu2+]
=2.710.05912log0.0010.0001
=2.710.02955
=2.68V
Thus, the EMF of the cell is 2.68V.

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