Calculate the energy in joule corresponding to light of wavelength 45 nm h -6-63 - 10-34 J s - C -3 - 108 ms -1A- 4-42 - 10-15B- 4-42 - 10-18C- 6-67 - 10-15D- 6-67 - 10-11

The correct option is B E = hc/λ = 6.63 × 10^ 34× 3 × 10^8/45 × 10^ 9=4.42 × 10^ 18J ...

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Standard XII

Physics

Photodiode

Calculate the...

Question

Calculate the energy in joule corresponding to light of wavelength $45 n m (h = 6.63 \times 10^{- 34} J s; C = 3 \times 10^{8} m s^{- 1})$

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Solution

The correct option is B
$E = \frac{h c}{λ} = \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{45 \times 10^{- 9}} = 4.42 \times 10^{- 18} J$

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Similar questions

Q. Calculate the energy in joule corresponding to light of wavelength 45 nm: (Planck's constant

h = 6.63 \times 10^{- 34} J s;

speed of light

c = 3 \times 10^{8} m s^{- 1}

)

Q. Calculate the energy of the light having wavelength 45 nm :

[Planck's constant

h = 6.63 \times 10^{- 34} J s

; speed of light

c = 3 \times 10^{8} m s^{- 1}

]

Q. Calculate the energy in joule corresponding to light of wavelength 45 nm.

(Planck's constant, h = 6.63 \times 10^{- 34} J . s, speed of light, c = 3 \times 10^{8} m . s^{- 1})

An important spectral emission line has a wavelength of 21 cm. The corresponding photon energy is
$(h = 6.62 \times 10^{- 34} J s$ ; $c = 3 \times 10^{8} m / s)$

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E = - 2.178 \times 10^{- 18} J (\frac{Z^{2}}{n^{2}})

wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be

(h = 6.62 \times 10^{- 34} J s a n d c = 3.0 \times 10^{8} m s^{- 1})

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Calculate the energy in joule corresponding to light of wavelength 45 nm (h=6.63×10−34Js;C=3×108ms−1)

The correct option is B E=hcλ=6.63×10−34×3×10845×10−9=4.42×10−18J

Calculate the energy in joule corresponding to light of wavelength $45 n m (h = 6.63 \times 10^{- 34} J s; C = 3 \times 10^{8} m s^{- 1})$

The correct option is B
$E = \frac{h c}{λ} = \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{45 \times 10^{- 9}} = 4.42 \times 10^{- 18} J$