Calculate the energy in joule corresponding to light of wavelength 45 nm h -6-63 - 10-34 J s - C -3 - 108 ms -1A- 4-42 - 10-15B- 4-42 - 10-18C- 6-67 - 10-15D- 6-67 - 10-11

The correct option is B E = hc/λ = 6.63 × 10^ 34× 3 × 10^8/45 × 10^ 9=4.42 × 10^ 18J ...

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Standard XII

Physics

Photodiode

Calculate the...

Question

Calculate the energy in joule corresponding to light of wavelength $45 n m (h = 6.63 \times 10^{- 34} J s; C = 3 \times 10^{8} m s^{- 1})$

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Solution

The correct option is B
$E = \frac{h c}{λ} = \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{45 \times 10^{- 9}} = 4.42 \times 10^{- 18} J$

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Similar questions

Q. Calculate the energy in joule corresponding to light of wavelength 45 nm: (Planck's constant

h = 6.63 \times 10^{- 34} J s;

speed of light

c = 3 \times 10^{8} m s^{- 1}

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Q. Calculate the energy of the light having wavelength 45 nm :

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h = 6.63 \times 10^{- 34} J s

; speed of light

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Q. Calculate the energy in joule corresponding to light of wavelength 45 nm.

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Calculate the energy in joule corresponding to light of wavelength 45 nm (h=6.63×10−34Js;C=3×108ms−1)

The correct option is B E=hcλ=6.63×10−34×3×10845×10−9=4.42×10−18J

Calculate the energy in joule corresponding to light of wavelength $45 n m (h = 6.63 \times 10^{- 34} J s; C = 3 \times 10^{8} m s^{- 1})$

The correct option is B
$E = \frac{h c}{λ} = \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{45 \times 10^{- 9}} = 4.42 \times 10^{- 18} J$