Question

Calculate the force of gravitation acting between a car of mass of 1000 Kg and earth. Mass of earth is $6\times {10}^{24}Kg$. The radius of earth $6.4\times {10}^{6}m$. The value of the universal gravitational constant is $6.67\times {10}^{-11}N{m}^2/K{g}^2$.

Answer 1

Step: 1 Given Data:

Mass of earth(M) = $6\times {10}^{24}Kg$

Mass of car (m) = $1000Kg$

Distance between car and the center of earth =The radius of earth (R)= $6.4\times {10}^{6}m$

The value of universal gravitational constant is $6.67\times {10}^{-11}N{m}^2/K{g}^2$

We need to find the gravitational force (F).

Step: 2 Formula used :

$F=G\frac{Mm}{R^2}$

Step: 3 Calculating the gravitational force (F) :

$F=6.67\times {10}^{-11}\frac{6\times {10}^{24}\times 1000}{{\left(6.4\times {10}^6\right)}^2}=9800N$

Hence,the gravitational force (F) is 9800 N.