Question

calculate the frequency, wave number and energy associated with photon of radiations having wavelength 6000 angestroms

Answer 1

$$\begin{gathered} Energy,E=\frac{hc}{\lambda } \\ =\frac{6.626\times {10}^{-34}\times 3\times {10}^8}{6000\times {10}^{-10}} \\ =3.313\times {10}^{-19}J \\ Frequency\nu =\frac{c}{\lambda }=5\times {10}^{-14}Hz \\ Wavenumber=\frac{1}{\lambda }=\frac{1}{6000\times {10}^{-10}}=1.67\times {10}^{-6}{m}^{-1} \end{gathered}$$